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- #include<cstdio>
- using namespace std;
- int n,a[40][40],x,y;
- int main(){
- scanf("%d",&n);
- x=1,y=(n+1)/2;
- for(int i=1;i<=n*n;i++){
- a[x][y]=i;
- if(!a[(x-2+n)%n+1][y%n+1]) x=(x-2+n)%n+1,y=y%n+1;
- else x=x%n+1;//数学运算
- }
- for(int i=1;i<=n;i++){
- for(int j=1;j<=n;j++){
- printf("%d ",a[i][j]);
- }
- printf("\n");
- }
- }
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发表于 2022-8-20 15:50:54
置顶卡